Integrand size = 23, antiderivative size = 183 \[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=-\frac {a \left (3 b^2-a^2 (1-m)\right ) (d \cos (e+f x))^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {3}{2},-\tan ^2(e+f x)\right ) \sec ^2(e+f x)^{m/2} \tan (e+f x)}{f (1-m)}+\frac {b (d \cos (e+f x))^m (a+b \tan (e+f x))^2}{f (2-m)}+\frac {b (d \cos (e+f x))^m \left (2 \left (b^2-a^2 (3-m)\right ) (1-m)+a b (4-m) m \tan (e+f x)\right )}{f m \left (2-3 m+m^2\right )} \]
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Time = 0.34 (sec) , antiderivative size = 175, normalized size of antiderivative = 0.96, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {3596, 3593, 757, 794, 251} \[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=\frac {a \left (a^2-\frac {3 b^2}{1-m}\right ) \tan (e+f x) \sec ^2(e+f x)^{m/2} (d \cos (e+f x))^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m+2}{2},\frac {3}{2},-\tan ^2(e+f x)\right )}{f}+\frac {b (d \cos (e+f x))^m \left (2 (1-m) \left (b^2-a^2 (3-m)\right )+a b (4-m) m \tan (e+f x)\right )}{f m \left (m^2-3 m+2\right )}+\frac {b (a+b \tan (e+f x))^2 (d \cos (e+f x))^m}{f (2-m)} \]
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Rule 251
Rule 757
Rule 794
Rule 3593
Rule 3596
Rubi steps \begin{align*} \text {integral}& = \left ((d \cos (e+f x))^m (d \sec (e+f x))^m\right ) \int (d \sec (e+f x))^{-m} (a+b \tan (e+f x))^3 \, dx \\ & = \frac {\left ((d \cos (e+f x))^m \sec ^2(e+f x)^{m/2}\right ) \text {Subst}\left (\int (a+x)^3 \left (1+\frac {x^2}{b^2}\right )^{-1-\frac {m}{2}} \, dx,x,b \tan (e+f x)\right )}{b f} \\ & = \frac {b (d \cos (e+f x))^m (a+b \tan (e+f x))^2}{f (2-m)}+\frac {\left (b (d \cos (e+f x))^m \sec ^2(e+f x)^{m/2}\right ) \text {Subst}\left (\int (a+x) \left (-2+\frac {a^2 (2-m)}{b^2}+\frac {a (4-m) x}{b^2}\right ) \left (1+\frac {x^2}{b^2}\right )^{-1-\frac {m}{2}} \, dx,x,b \tan (e+f x)\right )}{f (2-m)} \\ & = \frac {b (d \cos (e+f x))^m (a+b \tan (e+f x))^2}{f (2-m)}+\frac {b (d \cos (e+f x))^m \left (2 \left (b^2-a^2 (3-m)\right ) (1-m)+a b (4-m) m \tan (e+f x)\right )}{f m \left (2-3 m+m^2\right )}-\frac {\left (a \left (3 b^2-a^2 (1-m)\right ) (d \cos (e+f x))^m \sec ^2(e+f x)^{m/2}\right ) \text {Subst}\left (\int \left (1+\frac {x^2}{b^2}\right )^{-1-\frac {m}{2}} \, dx,x,b \tan (e+f x)\right )}{b f (1-m)} \\ & = -\frac {a \left (3 b^2-a^2 (1-m)\right ) (d \cos (e+f x))^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {3}{2},-\tan ^2(e+f x)\right ) \sec ^2(e+f x)^{m/2} \tan (e+f x)}{f (1-m)}+\frac {b (d \cos (e+f x))^m (a+b \tan (e+f x))^2}{f (2-m)}+\frac {b (d \cos (e+f x))^m \left (2 \left (b^2-a^2 (3-m)\right ) (1-m)+a b (4-m) m \tan (e+f x)\right )}{f m \left (2-3 m+m^2\right )} \\ \end{align*}
Time = 6.57 (sec) , antiderivative size = 212, normalized size of antiderivative = 1.16 \[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=\frac {\cos (e+f x) (d \cos (e+f x))^m \left (-\frac {b^3}{-2+m}+\frac {b \left (-3 a^2+b^2\right ) \cos ^2(e+f x)}{m}-\frac {a \left (a^2-3 b^2\right ) \cos ^3(e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\cos ^2(e+f x)\right ) \sin (e+f x)}{(1+m) \sqrt {\sin ^2(e+f x)}}-\frac {3 a b^2 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1}{2} (-1+m),\frac {1+m}{2},\cos ^2(e+f x)\right ) \sin (2 (e+f x))}{2 (-1+m) \sqrt {\sin ^2(e+f x)}}\right ) (a+b \tan (e+f x))^3}{f (a \cos (e+f x)+b \sin (e+f x))^3} \]
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\[\int \left (d \cos \left (f x +e \right )\right )^{m} \left (a +b \tan \left (f x +e \right )\right )^{3}d x\]
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\[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=\int { {\left (b \tan \left (f x + e\right ) + a\right )}^{3} \left (d \cos \left (f x + e\right )\right )^{m} \,d x } \]
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\[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=\int \left (d \cos {\left (e + f x \right )}\right )^{m} \left (a + b \tan {\left (e + f x \right )}\right )^{3}\, dx \]
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\[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=\int { {\left (b \tan \left (f x + e\right ) + a\right )}^{3} \left (d \cos \left (f x + e\right )\right )^{m} \,d x } \]
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\[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=\int { {\left (b \tan \left (f x + e\right ) + a\right )}^{3} \left (d \cos \left (f x + e\right )\right )^{m} \,d x } \]
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Timed out. \[ \int (d \cos (e+f x))^m (a+b \tan (e+f x))^3 \, dx=\int {\left (d\,\cos \left (e+f\,x\right )\right )}^m\,{\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^3 \,d x \]
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